X^2+3x-149=0

Solution for X^2+3x-149=0 equation:

X^2+3X-149=0

a = 1; b = 3; c = -149;
Δ = b2-4ac
Δ = 32-4·1·(-149)
Δ = 605
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{605}=\sqrt{121*5}=\sqrt{121}*\sqrt{5}=11\sqrt{5}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-11\sqrt{5}}{2*1}=\frac{-3-11\sqrt{5}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+11\sqrt{5}}{2*1}=\frac{-3+11\sqrt{5}}{2}
$